Optimal. Leaf size=128 \[ \frac {1}{3} d x \left (1-c^2 x^2\right ) \left (a+b \sin ^{-1}(c x)\right )^2+\frac {2 b d \left (1-c^2 x^2\right )^{3/2} \left (a+b \sin ^{-1}(c x)\right )}{9 c}+\frac {4 b d \sqrt {1-c^2 x^2} \left (a+b \sin ^{-1}(c x)\right )}{3 c}+\frac {2}{3} d x \left (a+b \sin ^{-1}(c x)\right )^2+\frac {2}{27} b^2 c^2 d x^3-\frac {14}{9} b^2 d x \]
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Rubi [A] time = 0.14, antiderivative size = 128, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 4, integrand size = 22, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.182, Rules used = {4649, 4619, 4677, 8} \[ \frac {1}{3} d x \left (1-c^2 x^2\right ) \left (a+b \sin ^{-1}(c x)\right )^2+\frac {2 b d \left (1-c^2 x^2\right )^{3/2} \left (a+b \sin ^{-1}(c x)\right )}{9 c}+\frac {4 b d \sqrt {1-c^2 x^2} \left (a+b \sin ^{-1}(c x)\right )}{3 c}+\frac {2}{3} d x \left (a+b \sin ^{-1}(c x)\right )^2+\frac {2}{27} b^2 c^2 d x^3-\frac {14}{9} b^2 d x \]
Antiderivative was successfully verified.
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Rule 8
Rule 4619
Rule 4649
Rule 4677
Rubi steps
\begin {align*} \int \left (d-c^2 d x^2\right ) \left (a+b \sin ^{-1}(c x)\right )^2 \, dx &=\frac {1}{3} d x \left (1-c^2 x^2\right ) \left (a+b \sin ^{-1}(c x)\right )^2+\frac {1}{3} (2 d) \int \left (a+b \sin ^{-1}(c x)\right )^2 \, dx-\frac {1}{3} (2 b c d) \int x \sqrt {1-c^2 x^2} \left (a+b \sin ^{-1}(c x)\right ) \, dx\\ &=\frac {2 b d \left (1-c^2 x^2\right )^{3/2} \left (a+b \sin ^{-1}(c x)\right )}{9 c}+\frac {2}{3} d x \left (a+b \sin ^{-1}(c x)\right )^2+\frac {1}{3} d x \left (1-c^2 x^2\right ) \left (a+b \sin ^{-1}(c x)\right )^2-\frac {1}{9} \left (2 b^2 d\right ) \int \left (1-c^2 x^2\right ) \, dx-\frac {1}{3} (4 b c d) \int \frac {x \left (a+b \sin ^{-1}(c x)\right )}{\sqrt {1-c^2 x^2}} \, dx\\ &=-\frac {2}{9} b^2 d x+\frac {2}{27} b^2 c^2 d x^3+\frac {4 b d \sqrt {1-c^2 x^2} \left (a+b \sin ^{-1}(c x)\right )}{3 c}+\frac {2 b d \left (1-c^2 x^2\right )^{3/2} \left (a+b \sin ^{-1}(c x)\right )}{9 c}+\frac {2}{3} d x \left (a+b \sin ^{-1}(c x)\right )^2+\frac {1}{3} d x \left (1-c^2 x^2\right ) \left (a+b \sin ^{-1}(c x)\right )^2-\frac {1}{3} \left (4 b^2 d\right ) \int 1 \, dx\\ &=-\frac {14}{9} b^2 d x+\frac {2}{27} b^2 c^2 d x^3+\frac {4 b d \sqrt {1-c^2 x^2} \left (a+b \sin ^{-1}(c x)\right )}{3 c}+\frac {2 b d \left (1-c^2 x^2\right )^{3/2} \left (a+b \sin ^{-1}(c x)\right )}{9 c}+\frac {2}{3} d x \left (a+b \sin ^{-1}(c x)\right )^2+\frac {1}{3} d x \left (1-c^2 x^2\right ) \left (a+b \sin ^{-1}(c x)\right )^2\\ \end {align*}
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Mathematica [A] time = 0.22, size = 137, normalized size = 1.07 \[ -\frac {d \left (9 a^2 c x \left (c^2 x^2-3\right )+6 a b \sqrt {1-c^2 x^2} \left (c^2 x^2-7\right )+6 b \sin ^{-1}(c x) \left (3 a c x \left (c^2 x^2-3\right )+b \sqrt {1-c^2 x^2} \left (c^2 x^2-7\right )\right )-2 b^2 c x \left (c^2 x^2-21\right )+9 b^2 c x \left (c^2 x^2-3\right ) \sin ^{-1}(c x)^2\right )}{27 c} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.96, size = 146, normalized size = 1.14 \[ -\frac {{\left (9 \, a^{2} - 2 \, b^{2}\right )} c^{3} d x^{3} - 3 \, {\left (9 \, a^{2} - 14 \, b^{2}\right )} c d x + 9 \, {\left (b^{2} c^{3} d x^{3} - 3 \, b^{2} c d x\right )} \arcsin \left (c x\right )^{2} + 18 \, {\left (a b c^{3} d x^{3} - 3 \, a b c d x\right )} \arcsin \left (c x\right ) + 6 \, {\left (a b c^{2} d x^{2} - 7 \, a b d + {\left (b^{2} c^{2} d x^{2} - 7 \, b^{2} d\right )} \arcsin \left (c x\right )\right )} \sqrt {-c^{2} x^{2} + 1}}{27 \, c} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.64, size = 196, normalized size = 1.53 \[ -\frac {1}{3} \, a^{2} c^{2} d x^{3} - \frac {1}{3} \, {\left (c^{2} x^{2} - 1\right )} b^{2} d x \arcsin \left (c x\right )^{2} - \frac {2}{3} \, {\left (c^{2} x^{2} - 1\right )} a b d x \arcsin \left (c x\right ) + \frac {2}{3} \, b^{2} d x \arcsin \left (c x\right )^{2} + \frac {2}{27} \, {\left (c^{2} x^{2} - 1\right )} b^{2} d x + \frac {4}{3} \, a b d x \arcsin \left (c x\right ) + \frac {2 \, {\left (-c^{2} x^{2} + 1\right )}^{\frac {3}{2}} b^{2} d \arcsin \left (c x\right )}{9 \, c} + a^{2} d x - \frac {40}{27} \, b^{2} d x + \frac {2 \, {\left (-c^{2} x^{2} + 1\right )}^{\frac {3}{2}} a b d}{9 \, c} + \frac {4 \, \sqrt {-c^{2} x^{2} + 1} b^{2} d \arcsin \left (c x\right )}{3 \, c} + \frac {4 \, \sqrt {-c^{2} x^{2} + 1} a b d}{3 \, c} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.06, size = 173, normalized size = 1.35 \[ \frac {-d \,a^{2} \left (\frac {1}{3} c^{3} x^{3}-c x \right )-d \,b^{2} \left (\frac {\arcsin \left (c x \right )^{2} \left (c^{2} x^{2}-3\right ) c x}{3}+\frac {4 c x}{3}-\frac {4 \arcsin \left (c x \right ) \sqrt {-c^{2} x^{2}+1}}{3}+\frac {2 \arcsin \left (c x \right ) \left (c^{2} x^{2}-1\right ) \sqrt {-c^{2} x^{2}+1}}{9}-\frac {2 \left (c^{2} x^{2}-3\right ) c x}{27}\right )-2 d a b \left (\frac {c^{3} x^{3} \arcsin \left (c x \right )}{3}-c x \arcsin \left (c x \right )+\frac {c^{2} x^{2} \sqrt {-c^{2} x^{2}+1}}{9}-\frac {7 \sqrt {-c^{2} x^{2}+1}}{9}\right )}{c} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [B] time = 0.43, size = 233, normalized size = 1.82 \[ -\frac {1}{3} \, b^{2} c^{2} d x^{3} \arcsin \left (c x\right )^{2} - \frac {1}{3} \, a^{2} c^{2} d x^{3} - \frac {2}{9} \, {\left (3 \, x^{3} \arcsin \left (c x\right ) + c {\left (\frac {\sqrt {-c^{2} x^{2} + 1} x^{2}}{c^{2}} + \frac {2 \, \sqrt {-c^{2} x^{2} + 1}}{c^{4}}\right )}\right )} a b c^{2} d - \frac {2}{27} \, {\left (3 \, c {\left (\frac {\sqrt {-c^{2} x^{2} + 1} x^{2}}{c^{2}} + \frac {2 \, \sqrt {-c^{2} x^{2} + 1}}{c^{4}}\right )} \arcsin \left (c x\right ) - \frac {c^{2} x^{3} + 6 \, x}{c^{2}}\right )} b^{2} c^{2} d + b^{2} d x \arcsin \left (c x\right )^{2} - 2 \, b^{2} d {\left (x - \frac {\sqrt {-c^{2} x^{2} + 1} \arcsin \left (c x\right )}{c}\right )} + a^{2} d x + \frac {2 \, {\left (c x \arcsin \left (c x\right ) + \sqrt {-c^{2} x^{2} + 1}\right )} a b d}{c} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int {\left (a+b\,\mathrm {asin}\left (c\,x\right )\right )}^2\,\left (d-c^2\,d\,x^2\right ) \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 1.28, size = 224, normalized size = 1.75 \[ \begin {cases} - \frac {a^{2} c^{2} d x^{3}}{3} + a^{2} d x - \frac {2 a b c^{2} d x^{3} \operatorname {asin}{\left (c x \right )}}{3} - \frac {2 a b c d x^{2} \sqrt {- c^{2} x^{2} + 1}}{9} + 2 a b d x \operatorname {asin}{\left (c x \right )} + \frac {14 a b d \sqrt {- c^{2} x^{2} + 1}}{9 c} - \frac {b^{2} c^{2} d x^{3} \operatorname {asin}^{2}{\left (c x \right )}}{3} + \frac {2 b^{2} c^{2} d x^{3}}{27} - \frac {2 b^{2} c d x^{2} \sqrt {- c^{2} x^{2} + 1} \operatorname {asin}{\left (c x \right )}}{9} + b^{2} d x \operatorname {asin}^{2}{\left (c x \right )} - \frac {14 b^{2} d x}{9} + \frac {14 b^{2} d \sqrt {- c^{2} x^{2} + 1} \operatorname {asin}{\left (c x \right )}}{9 c} & \text {for}\: c \neq 0 \\a^{2} d x & \text {otherwise} \end {cases} \]
Verification of antiderivative is not currently implemented for this CAS.
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